SQL语句练习50题(Mysql版)

@JAMMLY 2019年11月06日

摘要表名和字段 –1.学生表 Student(s_id,s_name,s_birth,s_sex) --学生编号,学生姓名, 出生年月,学生性别

表名和字段

–1.学生表

Student(s_id,s_name,s_birth,s_sex) --学生编号,学生姓名, 出生年月,学生性别

–2.课程表

Course(c_id,c_name,t_id) – --课程编号, 课程名称, 教师编号

–3.教师表

Teacher(t_id,t_name) --教师编号,教师姓名

–4.成绩表

Score(s_id,c_id,s_score) --学生编号,课程编号,分数


测试数据

--建表

--学生表

CREATE TABLE `Student`(

`s_id` VARCHAR(20),

`s_name` VARCHAR(20) NOT NULL DEFAULT '',

`s_birth` VARCHAR(20) NOT NULL DEFAULT '',

`s_sex` VARCHAR(10) NOT NULL DEFAULT '',

PRIMARY KEY(`s_id`)

);

--课程表

CREATE TABLE `Course`(

`c_id`  VARCHAR(20),

`c_name` VARCHAR(20) NOT NULL DEFAULT '',

`t_id` VARCHAR(20) NOT NULL,

PRIMARY KEY(`c_id`)

);

--教师表

CREATE TABLE `Teacher`(

`t_id` VARCHAR(20),

`t_name` VARCHAR(20) NOT NULL DEFAULT '',

PRIMARY KEY(`t_id`)

);

--成绩表

CREATE TABLE `Score`(

`s_id` VARCHAR(20),

`c_id`  VARCHAR(20),

`s_score` INT(3),

PRIMARY KEY(`s_id`,`c_id`)

);

--插入学生表测试数据

insert into Student values('01' , '赵雷' , '1990-01-01' , '男');

insert into Student values('02' , '钱电' , '1990-12-21' , '男');

insert into Student values('03' , '孙风' , '1990-05-20' , '男');

insert into Student values('04' , '李云' , '1990-08-06' , '男');

insert into Student values('05' , '周梅' , '1991-12-01' , '女');

insert into Student values('06' , '吴兰' , '1992-03-01' , '女');

insert into Student values('07' , '郑竹' , '1989-07-01' , '女');

insert into Student values('08' , '王菊' , '1990-01-20' , '女');

--课程表测试数据

insert into Course values('01' , '语文' , '02');

insert into Course values('02' , '数学' , '01');

insert into Course values('03' , '英语' , '03');


--教师表测试数据

insert into Teacher values('01' , '张三');

insert into Teacher values('02' , '李四');

insert into Teacher values('03' , '王五');


--成绩表测试数据

insert into Score values('01' , '01' , 80);

insert into Score values('01' , '02' , 90);

insert into Score values('01' , '03' , 99);

insert into Score values('02' , '01' , 70);

insert into Score values('02' , '02' , 60);

insert into Score values('02' , '03' , 80);

insert into Score values('03' , '01' , 80);

insert into Score values('03' , '02' , 80);

insert into Score values('03' , '03' , 80);

insert into Score values('04' , '01' , 50);

insert into Score values('04' , '02' , 30);

insert into Score values('04' , '03' , 20);

insert into Score values('05' , '01' , 76);

insert into Score values('05' , '02' , 87);

insert into Score values('06' , '01' , 31);

insert into Score values('06' , '03' , 34);

insert into Score values('07' , '02' , 89);

insert into Score values('07' , '03' , 98);


练习题和sql语句

-- 1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数

select a.* ,b.s_score as 01_score,c.s_score as 02_score from 

student a 

join score b on a.s_id=b.s_id and b.c_id='01'

left join score c on a.s_id=c.s_id and c.c_id='02' or c.c_id = NULL where b.s_score>c.s_score

--也可以这样写

select a.*,b.s_score as 01_score,c.s_score as 02_score from student   a,score b,score c 

where a.s_id=b.s_id 

and a.s_id=c.s_id 

and b.c_id='01' 

and c.c_id='02' 

and b.s_score>c.s_score

-- 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数

select a.* ,b.s_score as 01_score,c.s_score as 02_score from 

student a left join score b on a.s_id=b.s_id and b.c_id='01' or b.c_id=NULL 

join score c on a.s_id=c.s_id and c.c_id='02' where b.s_score<c.s_score

-- 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩

select b.s_id,b.s_name,ROUND(AVG(a.s_score),2) as avg_score from 

student b 

join score a on b.s_id = a.s_id

GROUP BY b.s_id,b.s_name HAVING avg_score >=60;

-- 4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩

-- (包括有成绩的和无成绩的)

select b.s_id,b.s_name,ROUND(AVG(a.s_score),2) as avg_score from 

student b 

left join score a on b.s_id = a.s_id

GROUP BY b.s_id,b.s_name HAVING avg_score <60

union

select a.s_id,a.s_name,0 as avg_score from 

student a 

where a.s_id not in (

select distinct s_id from score);


-- 5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩

select a.s_id,a.s_name,count(b.c_id) as sum_course,sum(b.s_score) as sum_score from 

student a 

left join score b on a.s_id=b.s_id

GROUP BY a.s_id,a.s_name;

-- 6、查询"李"姓老师的数量 

select count(t_id) from teacher where t_name like '李%';

-- 7、查询学过"张三"老师授课的同学的信息 

select a.* from 

student a 

join score b on a.s_id=b.s_id where b.c_id in(

select c_id from course where t_id =(

select t_id from teacher where t_name = '张三'));


-- 8、查询没学过"张三"老师授课的同学的信息 

select * from 

    student c 

    where c.s_id not in(

        select a.s_id from student a join score b on a.s_id=b.s_id where b.c_id in(

        select a.c_id from course a join teacher b on a.t_id = b.t_id where t_name ='张三'));

-- 9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息


select a.* from 

student a,score b,score c 

where a.s_id = b.s_id  and a.s_id = c.s_id and b.c_id='01' and c.c_id='02';

-- 10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息

select a.* from 

student a 

where a.s_id in (select s_id from score where c_id='01' ) and a.s_id not in(select s_id from score where c_id='02')

-- 11、查询没有学全所有课程的同学的信息 

--@wendiepei的写法

select s.* from student s 

left join Score s1 on s1.s_id=s.s_id

group by s.s_id having count(s1.c_id)<(select count(*) from course)

--@k1051785839的写法

select *

from student

where s_id not in(

select s_id from score t1  

group by s_id having count(*) =(select count(distinct c_id)  from course)) 

-- 12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息 


select * from student where s_id in(

select distinct a.s_id from score a where a.c_id in(select a.c_id from score a where a.s_id='01')

);

-- 13、查询和"01"号的同学学习的课程完全相同的其他同学的信息 

--@ouyang_1993的写法

SELECT

 Student.*

FROM

 Student

WHERE

 s_id IN (SELECT s_id FROM Score GROUP BY s_id HAVING COUNT(s_id) = (

    #下面的语句是找到'01'同学学习的课程数

    SELECT COUNT(c_id) FROM Score WHERE s_id = '01'

   )

 )

AND s_id NOT IN (

 #下面的语句是找到学过‘01’同学没学过的课程,有哪些同学。并排除他们

 SELECT s_id FROM Score

 WHERE c_id IN(

   #下面的语句是找到‘01’同学没学过的课程

   SELECT DISTINCT c_id FROM Score

   WHERE c_id NOT IN (

     #下面的语句是找出‘01’同学学习的课程

     SELECT c_id FROM Score WHERE s_id = '01'

    )

  ) GROUP BY s_id

) #下面的条件是排除01同学

AND s_id NOT IN ('01')

--@k1051785839的写法

SELECT

 t3.*

FROM

 (

  SELECT

   s_id,

   group_concat(c_id ORDER BY c_id) group1

  FROM

   score

  WHERE

   s_id &lt;> '01'

  GROUP BY

   s_id

 ) t1

INNER JOIN (

 SELECT

  group_concat(c_id ORDER BY c_id) group2

 FROM

  score

 WHERE

  s_id = '01'

 GROUP BY

  s_id

) t2 ON t1.group1 = t2.group2

INNER JOIN student t3 ON t1.s_id = t3.s_id


-- 14、查询没学过"张三"老师讲授的任一门课程的学生姓名 

select a.s_name from student a where a.s_id not in (

select s_id from score where c_id = 

(select c_id from course where t_id =(

select t_id from teacher where t_name = '张三')));


-- 15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩 

select a.s_id,a.s_name,ROUND(AVG(b.s_score)) from 

student a 

left join score b on a.s_id = b.s_id

where a.s_id in(

select s_id from score where s_score<60 GROUP BY  s_id having count(1)>=2)

GROUP BY a.s_id,a.s_name


-- 16、检索"01"课程分数小于60,按分数降序排列的学生信息

select a.*,b.c_id,b.s_score from 

student a,score b 

where a.s_id = b.s_id and b.c_id='01' and b.s_score<60 ORDER BY b.s_score DESC;

-- 17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩

select a.s_id,(select s_score from score where s_id=a.s_id and c_id='01') as 语文,

(select s_score from score where s_id=a.s_id and c_id='02') as 数学,

(select s_score from score where s_id=a.s_id and c_id='03') as 英语,

round(avg(s_score),2) as 平均分 from score a  GROUP BY a.s_id ORDER BY 平均分 DESC;

--@喝完这杯还有一箱的写法

SELECT a.s_id,MAX(CASE a.c_id WHEN '01' THEN a.s_score END ) 语文, 

MAX(CASE a.c_id WHEN '02' THEN a.s_score END ) 数学, 

MAX(CASE a.c_id WHEN '03' THEN a.s_score END ) 英语, 

avg(a.s_score),b.s_name FROM Score a JOIN Student b ON a.s_id=b.s_id GROUP BY a.s_id ORDER BY 5 DESC

-- 18.查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率

--及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90

select a.c_id,b.c_name,MAX(s_score),MIN(s_score),ROUND(AVG(s_score),2),

ROUND(100*(SUM(case when a.s_score>=60 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 及格率,

ROUND(100*(SUM(case when a.s_score>=70 and a.s_score<=80 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 中等率,

ROUND(100*(SUM(case when a.s_score>=80 and a.s_score<=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 优良率,

ROUND(100*(SUM(case when a.s_score>=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 优秀率

from score a left join course b on a.c_id = b.c_id GROUP BY a.c_id,b.c_name

-- 19、按各科成绩进行排序,并显示排名

-- mysql没有rank函数

select a.s_id,a.c_id,

        @i:=@i +1 as i保留排名,

        @k:=(case when @score=a.s_score then @k else @i end) as rank不保留排名,

        @score:=a.s_score as score

    from (

        select s_id,c_id,s_score from score GROUP BY s_id,c_id,s_score ORDER BY s_score DESC

)a,(select @k:=0,@i:=0,@score:=0)s

--@k1051785839的写法

(select * from (select 

t1.c_id,

t1.s_score,

(select count(distinct t2.s_score) from score t2 where t2.s_score>=t1.s_score and t2.c_id='01') rank

FROM score t1 where t1.c_id='01'

order by t1.s_score desc) t1)

union

(select * from (select 

t1.c_id,

t1.s_score,

(select count(distinct t2.s_score) from score t2 where t2.s_score>=t1.s_score and t2.c_id='02') rank

FROM score t1 where t1.c_id='02'

order by t1.s_score desc) t2)

union

(select * from (select 

t1.c_id,

t1.s_score,

(select count(distinct t2.s_score) from score t2 where t2.s_score>=t1.s_score and t2.c_id='03') rank

FROM score t1 where t1.c_id='03'

order by t1.s_score desc) t3)

-- 20、查询学生的总成绩并进行排名

select a.s_id,

@i:=@i+1 as i,

@k:=(case when @score=a.sum_score then @k else @i end) as rank,

@score:=a.sum_score as score

from (select s_id,SUM(s_score) as sum_score from score GROUP BY s_id ORDER BY sum_score DESC)a,

(select @k:=0,@i:=0,@score:=0)s

-- 21、查询不同老师所教不同课程平均分从高到低显示 

select a.t_id,c.t_name,a.c_id,ROUND(avg(s_score),2) as avg_score from course a

left join score b on a.c_id=b.c_id 

left join teacher c on a.t_id=c.t_id

GROUP BY a.c_id,a.t_id,c.t_name ORDER BY avg_score DESC;

-- 22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

select d.*,c.排名,c.s_score,c.c_id from (

                select a.s_id,a.s_score,a.c_id,@i:=@i+1 as 排名 from score a,(select @i:=0)s where a.c_id='01'  

ORDER BY a.s_score DESC  

            )c

            left join student d on c.s_id=d.s_id

            where 排名 BETWEEN 2 AND 3

            UNION

            select d.*,c.排名,c.s_score,c.c_id from (

                select a.s_id,a.s_score,a.c_id,@j:=@j+1 as 排名 from score a,(select @j:=0)s where a.c_id='02'  

ORDER BY a.s_score DESC

            )c

            left join student d on c.s_id=d.s_id

            where 排名 BETWEEN 2 AND 3

            UNION

            select d.*,c.排名,c.s_score,c.c_id from (

                select a.s_id,a.s_score,a.c_id,@k:=@k+1 as 排名 from score a,(select @k:=0)s where a.c_id='03' 

ORDER BY a.s_score DESC

            )c

            left join student d on c.s_id=d.s_id

            where 排名 BETWEEN 2 AND 3;

-- 23、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比


select distinct f.c_name,a.c_id,b.`85-100`,b.百分比,c.`70-85`,c.百分比,d.`60-70`,d.百分比,e.`0-60`,e.百分比 from score a

left join (select c_id,SUM(case when s_score >85 and s_score <=100 then 1 else 0 end) as `85-100`,

ROUND(100*(SUM(case when s_score >85 and s_score <=100 then 1 else 0 end)/count(*)),2) as 百分比

from score GROUP BY c_id)b on a.c_id=b.c_id

left join (select c_id,SUM(case when s_score >70 and s_score <=85 then 1 else 0 end) as `70-85`,

ROUND(100*(SUM(case when s_score >70 and s_score <=85 then 1 else 0 end)/count(*)),2) as 百分比

from score GROUP BY c_id)c on a.c_id=c.c_id

left join (select c_id,SUM(case when s_score >60 and s_score <=70 then 1 else 0 end) as `60-70`,

ROUND(100*(SUM(case when s_score >60 and s_score <=70 then 1 else 0 end)/count(*)),2) as 百分比

from score GROUP BY c_id)d on a.c_id=d.c_id

left join (select c_id,SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end) as `0-60`,

ROUND(100*(SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end)/count(*)),2) as 百分比

from score GROUP BY c_id)e on a.c_id=e.c_id

left join course f on a.c_id = f.c_id

 

-- 24、查询学生平均成绩及其名次 


select a.s_id,

@i:=@i+1 as '不保留空缺排名',

@k:=(case when @avg_score=a.avg_s then @k else @i end) as '保留空缺排名',

@avg_score:=avg_s as '平均分'

from (select s_id,ROUND(AVG(s_score),2) as avg_s from score GROUP BY s_id ORDER BY avg_s DESC)a,(select @avg_score:=0,@i:=0,@k:=0)b;

-- 25、查询各科成绩前三名的记录

-- 1.选出b表比a表成绩大的所有组

-- 2.选出比当前id成绩大的 小于三个的

select a.s_id,a.c_id,a.s_score from score a 

left join score b on a.c_id = b.c_id and a.s_score<b.s_score

group by a.s_id,a.c_id,a.s_score HAVING COUNT(b.s_id)<3

ORDER BY a.c_id,a.s_score DESC


-- 26、查询每门课程被选修的学生数 


select c_id,count(s_id) from score a GROUP BY c_id


-- 27、查询出只有两门课程的全部学生的学号和姓名 

select s_id,s_name from student where s_id in(

select s_id from score GROUP BY s_id HAVING COUNT(c_id)=2);


-- 28、查询男生、女生人数 

select s_sex,COUNT(s_sex) as 人数  from student GROUP BY s_sex


-- 29、查询名字中含有"风"字的学生信息


select * from student where s_name like '%风%';


-- 30、查询同名同性学生名单,并统计同名人数 

select a.s_name,a.s_sex,count(*) from student a  JOIN 

student b on a.s_id !=b.s_id and a.s_name = b.s_name and a.s_sex = b.s_sex

GROUP BY a.s_name,a.s_sex


-- 31、查询1990年出生的学生名单

select s_name from student where s_birth like '1990%'


-- 32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列 


select c_id,ROUND(AVG(s_score),2) as avg_score from score GROUP BY c_id ORDER BY avg_score DESC,c_id ASC


-- 33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩 


select a.s_id,b.s_name,ROUND(avg(a.s_score),2) as avg_score from score a

left join student b on a.s_id=b.s_id GROUP BY s_id HAVING avg_score>=85

-- 34、查询课程名称为"数学",且分数低于60的学生姓名和分数 

select a.s_name,b.s_score from score b join student a on a.s_id=b.s_id where b.c_id=(

select c_id from course where c_name ='数学') and b.s_score<60


-- 35、查询所有学生的课程及分数情况; 

select a.s_id,a.s_name,

SUM(case c.c_name when '语文' then b.s_score else 0 end) as '语文',

SUM(case c.c_name when '数学' then b.s_score else 0 end) as '数学',

SUM(case c.c_name when '英语' then b.s_score else 0 end) as '英语',

SUM(b.s_score) as  '总分'

from student a left join score b on a.s_id = b.s_id 

left join course c on b.c_id = c.c_id 

GROUP BY a.s_id,a.s_name


 -- 36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数; 

select a.s_name,b.c_name,c.s_score from course b left join score c on b.c_id = c.c_id

left join student a on a.s_id=c.s_id where c.s_score>=70


-- 37、查询不及格的课程

select a.s_id,a.c_id,b.c_name,a.s_score from score a left join course b on a.c_id = b.c_id

where a.s_score<60 

--38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名; 

select a.s_id,b.s_name from score a LEFT JOIN student b on a.s_id = b.s_id

where a.c_id = '01' and a.s_score>80


-- 39、求每门课程的学生人数 

select count(*) from score GROUP BY c_id;


-- 40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩


-- 查询老师id

select c_id from course c,teacher d where c.t_id=d.t_id and d.t_name='张三'

-- 查询最高分(可能有相同分数)

select MAX(s_score) from score where c_id='02'

-- 查询信息

select a.*,b.s_score,b.c_id,c.c_name from student a

LEFT JOIN score b on a.s_id = b.s_id

LEFT JOIN course c on b.c_id=c.c_id

where b.c_id =(select c_id from course c,teacher d where c.t_id=d.t_id and d.t_name='张三')

and b.s_score in (select MAX(s_score) from score where c_id='02')


-- 41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩 

select DISTINCT b.s_id,b.c_id,b.s_score from score a,score b where a.c_id != b.c_id and a.s_score = b.s_score

-- 42、查询每门功成绩最好的前两名 

-- 牛逼的写法

select a.s_id,a.c_id,a.s_score from score a

where (select COUNT(1) from score b where b.c_id=a.c_id and b.s_score>=a.s_score)<=2 ORDER BY a.c_id


-- 43、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列  

select c_id,count(*) as total from score GROUP BY c_id HAVING total>5 ORDER BY total,c_id ASC

-- 44、检索至少选修两门课程的学生学号 

select s_id,count(*) as sel from score GROUP BY s_id HAVING sel>=2


-- 45、查询选修了全部课程的学生信息 

select * from student where s_id in(

select s_id from score GROUP BY s_id HAVING count(*)=(select count(*) from course))


--46、查询各学生的年龄

-- 按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一


select s_birth,(DATE_FORMAT(NOW(),'%Y')-DATE_FORMAT(s_birth,'%Y') - 

(case when DATE_FORMAT(NOW(),'%m%d')>DATE_FORMAT(s_birth,'%m%d') then 0 else 1 end)) as age

from student;


-- 47、查询本周过生日的学生

select * from student where WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))=WEEK(s_birth)

select * from student where YEARWEEK(s_birth)=YEARWEEK(DATE_FORMAT(NOW(),'%Y%m%d'))

select WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))


-- 48、查询下周过生日的学生

select * from student where WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))+1 =WEEK(s_birth)


-- 49、查询本月过生日的学生


select * from student where MONTH(DATE_FORMAT(NOW(),'%Y%m%d')) =MONTH(s_birth)

-- 50、查询下月过生日的学生

select * from student where MONTH(DATE_FORMAT(NOW(),'%Y%m%d'))+1 =MONTH(s_birth)



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